Question

09/03 - segment bisector practice l (updated)
given: y is the midpoint of wz. find the following lengths.
w 2x + 3 y 27 z
equation: (no space)
x =
wy =
wz =

Explanation:

Step1: Set up the equation

Since Y is the mid - point of WZ, then WY = YZ. So the equation is $2x + 3=27$.

Step2: Solve for x

Subtract 3 from both sides of the equation: $2x=27 - 3$, so $2x = 24$. Then divide both sides by 2: $x=\frac{24}{2}=12$.

Step3: Find the length of WY

Substitute x = 12 into the expression for WY. WY=$2x + 3$, so WY=$2\times12+3=24 + 3=27$.

Step4: Find the length of WZ

Since WZ=WY + YZ and WY = YZ = 27, then WZ=27+27 = 54.

Answer:

Equation: $2x + 3=27$
$x = 12$
WY = 27
WZ = 54