Question

1. p(2, -1), q(-3, -1), r(-11, 9), s(-7, 9)

table with columns: ( mleft(overleftrightarrow{pq}
ight) ), ( mleft(overleftrightarrow{rs}
ight) ), types of lines, with empty rows below each column

Explanation:

Step1: Calculate slope of \( \overleftrightarrow{PQ} \)

The slope formula is \( m = \frac{y_2 - y_1}{x_2 - x_1} \). For \( P(2, -1) \) and \( Q(-3, -1) \), \( y_2 - y_1 = -1 - (-1) = 0 \), \( x_2 - x_1 = -3 - 2 = -5 \). So \( m(\overleftrightarrow{PQ}) = \frac{0}{-5} = 0 \).

Step2: Calculate slope of \( \overleftrightarrow{RS} \)

For \( R(-11, 9) \) and \( S(-7, 9) \), \( y_2 - y_1 = 9 - 9 = 0 \), \( x_2 - x_1 = -7 - (-11) = 4 \). So \( m(\overleftrightarrow{RS}) = \frac{0}{4} = 0 \).

Step3: Determine line type

Since both slopes are 0, the lines are horizontal (and parallel, as equal slopes imply parallel lines).

Answer:

\( m(\overleftrightarrow{PQ}) \)	\( m(\overleftrightarrow{RS}) \)	Types of Lines