Question

is (-10, -8) a solution to this system of equations?
5x - 5y = -10
14x - 19y = 12
yes
no

Explanation:

Step1: Substitute into first equation

Substitute \(x = - 10\) and \(y=-8\) into \(5x - 5y=-10\).
\[

$$\begin{align*} 5\times(-10)-5\times(-8)&=-50 + 40\\ &=-10 \end{align*}$$

\]
The left - hand side equals the right - hand side for the first equation.

Step2: Substitute into second equation

Substitute \(x = - 10\) and \(y = - 8\) into \(14x-19y = 12\).
\[

$$\begin{align*} 14\times(-10)-19\times(-8)&=-140+152\\ &=12 \end{align*}$$

\]
The left - hand side equals the right - hand side for the second equation.

Answer:

yes