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k. \\log_{10} 4 + \\log_{10} x = 2

Question

k. \log_{10} 4 + \log_{10} x = 2

Explanation:

Step1: Apply log product rule

$\log_{10}(4x) = 2$

Step2: Convert to exponential form

$4x = 10^2$

Step3: Calculate $10^2$ and simplify

$4x = 100$

Step4: Solve for x

$x = \frac{100}{4}$

Answer:

$x = 25$