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Question
- $6p - 10 = 26$
- $\frac{n}{10}-20 = 0$
- $\frac{h}{4}+1 = 9$
- $9s - 40 = 41$
- $14 = 2c + 8$
- $8 = 5d - 12$
- $6=\frac{m}{3}-9$
- $4w - 6 = 10$
- $\frac{f}{3}+2 = 11$
Problem 7: \(6p - 10 = 26\)
Step 1: Add 10 to both sides
To isolate the term with \(p\), we add 10 to both sides of the equation. This gives us \(6p - 10 + 10 = 26 + 10\), which simplifies to \(6p = 36\).
Step 2: Divide by 6
Now, we divide both sides by 6 to solve for \(p\). So, \(\frac{6p}{6} = \frac{36}{6}\), which simplifies to \(p = 6\).
Step 1: Add 20 to both sides
To isolate the term with \(n\), we add 20 to both sides. This gives \(\frac{n}{10} - 20 + 20 = 0 + 20\), simplifying to \(\frac{n}{10} = 20\).
Step 2: Multiply by 10
Multiply both sides by 10 to solve for \(n\). So, \(\frac{n}{10} \times 10 = 20 \times 10\), which gives \(n = 200\).
Step 1: Subtract 1 from both sides
To isolate the term with \(h\), we subtract 1 from both sides. This gives \(\frac{h}{4} + 1 - 1 = 9 - 1\), simplifying to \(\frac{h}{4} = 8\).
Step 2: Multiply by 4
Multiply both sides by 4 to solve for \(h\). So, \(\frac{h}{4} \times 4 = 8 \times 4\), which gives \(h = 32\).
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\(p = 6\)