Question

1. \five times the difference of twice a number and three, decreased by the sum of the number and eight, equals 13.\

Explanation:

Step1: Define the unknown number

Let the number be $x$.

Step2: Translate to equation

$5(2x - 3) - (x + 8) = 13$

Step3: Expand the brackets

$10x - 15 - x - 8 = 13$

Step4: Combine like terms

$9x - 23 = 13$

Step5: Isolate the variable term

$9x = 13 + 23$
$9x = 36$

Step6: Solve for x

$x = \frac{36}{9}$

Answer:

$x = 4$