QUESTION IMAGE
Question
- what is $f(g(x))$?
$f(x) = 3x + 5$ and $g(x) = 5x - 1$
$\bigcirc$ $f(g(x)) = 15x + 24$
$\bigcirc$ $f(g(x)) = 15x + 2$
$\bigcirc$ $f(g(x)) = 15x - 1$
$\bigcirc$ $f(g(x)) = 15x + 5$
- multiply the matrices.
$1, 2, 3 \
$
$\bigcirc$ $12$
$\bigcirc$ $2$
$\bigcirc$ $2$
$\bigcirc$ $\
$
- use the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ to find the roots of the quadratic equation.
$y = x^2 + x + 1$
$\bigcirc$ $x = -\frac{1}{2} \pm i\frac{\sqrt{5}}{2}$
$\bigcirc$ $x = -\frac{1}{2} \pm i\frac{\sqrt{3}}{2}$
$\bigcirc$ $x = -\frac{1}{2} \pm \frac{\sqrt{3}}{2}$
$\bigcirc$ $x = -\frac{1}{2} \pm \frac{\sqrt{5}}{2}$
Question 10
Step1: Substitute $g(x)$ into $f(x)$
$f(g(x)) = 3(5x-1) + 5$
Step2: Expand and simplify
$f(g(x)) = 15x - 3 + 5 = 15x + 2$
Step1: Compute matrix dot product
$(1\times3) + (2\times1) + (3\times(-1))$
Step2: Calculate the sum
$3 + 2 - 3 = 2$
Step1: Identify $a,b,c$
For $y=x^2+x+1$, $a=1$, $b=1$, $c=1$
Step2: Substitute into quadratic formula
$x = \frac{-1\pm\sqrt{1^2-4(1)(1)}}{2(1)}$
Step3: Simplify discriminant
$\sqrt{1-4} = \sqrt{-3} = i\sqrt{3}$
Step4: Final simplification
$x = -\frac{1}{2} \pm i\frac{\sqrt{3}}{2}$
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$f(g(x)) = 15x + 2$
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