Question

1. what is the energy of a 9.33 x 10^-3 m wave?

Explanation:

Step1: Recall the energy - wavelength formula

The energy of a photon is given by $E = h\frac{c}{\lambda}$, where $h = 6.626\times10^{-34}\text{ J}\cdot\text{s}$ (Planck's constant), $c = 3\times 10^{8}\text{ m/s}$ (speed of light) and $\lambda$ is the wavelength.

Step2: Substitute the given values

We have $\lambda=9.33\times 10^{-3}\text{ m}$, $h = 6.626\times10^{-34}\text{ J}\cdot\text{s}$ and $c = 3\times 10^{8}\text{ m/s}$.
$E=\frac{6.626\times 10^{-34}\text{ J}\cdot\text{s}\times3\times 10^{8}\text{ m/s}}{9.33\times 10^{-3}\text{ m}}$

Step3: Calculate the energy

First, calculate the numerator: $6.626\times 10^{-34}\times3\times 10^{8}=19.878\times 10^{-26}\text{ J}\cdot\text{m}$.
Then, divide by the denominator: $E=\frac{19.878\times 10^{-26}\text{ J}\cdot\text{m}}{9.33\times 10^{-3}\text{ m}}\approx2.13\times 10^{-23}\text{ J}$

Answer:

$2.13\times 10^{-23}\text{ J}$