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Question
b) \\(\frac{3}{5}(10x - 55) + (7x - 6)\\) (with some partial text above: in factored form. sh)
Step1: Distribute the fraction
$\frac{3}{5}(10x - 55) = \frac{3}{5} \cdot 10x - \frac{3}{5} \cdot 55 = 6x - 33$
Step2: Combine like terms
$(6x - 33) + (7x - 6) = (6x + 7x) + (-33 - 6) = 13x - 39$
Step3: Factor out the GCF
$\text{GCF of } 13x \text{ and } 39 \text{ is } 13, \text{ so } 13x - 39 = 13(x - 3)$
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$13(x - 3)$