Question

10x - 7y = -11\
7x - 7y = 7\
(\boxed{})(\boxed{})\
submit

Explanation:

Step1: Subtract the two equations

We have the equations:

1. \(10x - 7y=- 11\)
2. \(7x - 7y = 7\)

Subtract the second equation from the first equation: \((10x - 7y)-(7x - 7y)=-11 - 7\)

Step2: Simplify the left - hand side

Simplify \((10x - 7y)-(7x - 7y)\):
\[

$$\begin{align*} 10x-7y - 7x + 7y&=(10x-7x)+(-7y + 7y)\\ &=3x \end{align*}$$

\]

Step3: Simplify the right - hand side

Simplify \(-11 - 7=-18\)

So we get \(3x=-18\)

Step4: Solve for x

Divide both sides of \(3x = - 18\) by 3: \(x=\frac{-18}{3}=-6\)

Step5: Substitute x into one of the equations

Substitute \(x = - 6\) into the second equation \(7x-7y = 7\):

\(7\times(-6)-7y = 7\)

Step6: Simplify the left - hand side

\(7\times(-6)-7y=-42-7y\)

So the equation becomes \(-42-7y = 7\)

Step7: Solve for y

Add 42 to both sides: \(-7y=7 + 42=49\)

Divide both sides by - 7: \(y=\frac{49}{-7}=-7\)

Answer:

If we assume the problem is to solve the system of equations \(

$$\begin{cases}10x - 7y=-11\\7x - 7y = 7\end{cases}$$

\), then \(x=-6\) and \(y = - 7\)