Question

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11 $(9, 2); (3, -1)$
12 $(-5, 8); (-4, 2)$
13 $(0, -1); (4, -7)$
14 $(1, -1); (-2, -6)$
ar 9
ig $\frac{1}{2}$
at $-\frac{7}{2}$
ob $-\frac{7}{6}$

Explanation:

These problems are calculating the slope between two points \((x_1,y_1)\) and \((x_2,y_2)\) using the slope formula \(m=\frac{y_2-y_1}{x_2-x_1}\)

Step1: Calculate slope for (11)

Substitute \((9,2)\) and \((3,-1)\) into formula:
\(m=\frac{-1-2}{3-9}=\frac{-3}{-6}=\frac{1}{2}\)

Step2: Calculate slope for (12)

Substitute \((-5,8)\) and \((-4,2)\) into formula:
\(m=\frac{2-8}{-4-(-5)}=\frac{-6}{1}=-6\)

Step3: Calculate slope for (13)

Substitute \((0,-1)\) and \((4,-7)\) into formula:
\(m=\frac{-7-(-1)}{4-0}=\frac{-6}{4}=-\frac{3}{2}\)

Step4: Calculate slope for (14)

Substitute \((1,-1)\) and \((-2,-6)\) into formula:
\(m=\frac{-6-(-1)}{-2-1}=\frac{-5}{-3}=\frac{5}{3}\)

Answer:

1. $\frac{1}{2}$
2. $-6$
3. $-\frac{3}{2}$
4. $\frac{5}{3}$