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11) challenge: \\begin{cases}8x + 4y = 24 \\\\ 2x + 6y = 56\\end{cases}

Question

  1. challenge: \
$$\begin{cases}8x + 4y = 24 \\\\ 2x + 6y = 56\\end{cases}$$

Explanation:

Step1: Simplify first equation

Divide by 4: $2x + y = 6$

Step2: Simplify second equation

Divide by 2: $x + 3y = 28$

Step3: Isolate $x$ from Step2

$x = 28 - 3y$

Step4: Substitute $x$ into Step1 equation

$2(28 - 3y) + y = 6$
Expand: $56 - 6y + y = 6$
Simplify: $56 - 5y = 6$

Step5: Solve for $y$

$-5y = 6 - 56$
$-5y = -50$
$y = 10$

Step6: Substitute $y$ into $x$ expression

$x = 28 - 3(10)$
$x = 28 - 30$
$x = -2$

Answer:

$x=-2$, $y=10$