Question

1. for a hydrogen atom, which of the following electronic energy level transitions represents a photon absorption event?

\ta. n=1 to n=3
\tb. n=4 to n=2
\tc. n=5 to n=4
\td. n=4 to n=1
12 what is the frequency (ν) in hz of a photon with a wavelength of 470 nm?

Explanation:

Photon absorption occurs when an electron in a hydrogen atom moves from a lower energy level (lower principal quantum number $n$) to a higher energy level (higher $n$). Emission happens when electrons move from higher to lower $n$.

• Option a: $n=1$ (lower) to $n=3$ (higher) is absorption.
• Options b, c, d: All involve electrons moving from higher to lower $n$, which are emission events.

Answer:

a. n=1 to n=3