Question

w.11 multiply polynomials 58a
find the product. simplify your answer.
$(3n - 3)(4n^{2} - 4n - 3)$

Explanation:

Step1: Distribute $3n$ to each term

$3n \cdot 4n^2 + 3n \cdot (-4n) + 3n \cdot (-3)$
$= 12n^3 - 12n^2 - 9n$

Step2: Distribute $-3$ to each term

$-3 \cdot 4n^2 + (-3) \cdot (-4n) + (-3) \cdot (-3)$
$= -12n^2 + 12n + 9$

Step3: Combine all resulting terms

$12n^3 - 12n^2 - 9n - 12n^2 + 12n + 9$

Step4: Combine like terms

$12n^3 + (-12n^2 -12n^2) + (-9n +12n) +9$
$=12n^3 -24n^2 +3n +9$

Answer:

$12n^3 - 24n^2 + 3n + 9$