QUESTION IMAGE
Question
- use the simple interest formula to find the missing entries in the table. round monetary amounts to the nearest cent.
| interest | principal | rate to the nearest hundredth of a percent | time | ---------- | ----------- | -------------------------------------------- | ------ | a. | $2,000 | 3.35% | 4 years | b. | $3,500 | 4.1% | 15 months | c. | $20,100 | 5.5% | 400 days | $100 | $700 | 8.8% | d. | $250 | $3,000 | $4\frac{3}{4}%$ | e. | $500 | $3,000 | f. | 3 years | $500 | g. | 4.4% | 30 months | x | p | 3% | h. |
The simple interest formula is $I = P \times r \times t$, where:
- $I$ = Interest
- $P$ = Principal
- $r$ = annual interest rate (decimal form)
- $t$ = time in years
---
Step1: Solve for a. (Find I)
Convert rate to decimal: $3.35\% = 0.0335$
Time is already in years.
$I = 2000 \times 0.0335 \times 4$
$I = 2000 \times 0.134 = 268$
Step2: Solve for b. (Find I)
Convert rate to decimal: $4.1\% = 0.041$
Convert months to years: $t = \frac{15}{12} = 1.25$
$I = 3500 \times 0.041 \times 1.25$
$I = 3500 \times 0.05125 = 179.375$
Step3: Solve for c. (Find I)
Convert rate to decimal: $5.5\% = 0.055$
Convert days to years: $t = \frac{400}{365}$
$I = 20100 \times 0.055 \times \frac{400}{365}$
$I = 20100 \times 0.055 \times 1.09589 \approx 1210.68$
Step4: Solve for d. (Find r)
Rearrange formula: $r = \frac{I}{P \times t}$
Convert days to years: $t = \frac{400}{365}$
$r = \frac{100}{700 \times \frac{400}{365}} = \frac{100 \times 365}{700 \times 400} = \frac{36500}{280000} \approx 0.1304$
Convert to percent: $0.1304 \times 100 = 13.04\%$
Step5: Solve for e. (Find t)
Rearrange formula: $t = \frac{I}{P \times r}$
Convert rate to decimal: $4\frac{3}{4}\% = 4.75\% = 0.0475$
$t = \frac{250}{3000 \times 0.0475} = \frac{250}{142.5} \approx 1.75$ years
Step6: Solve for f. (Find P)
Rearrange formula: $P = \frac{I}{r \times t}$
Convert rate to decimal: $4.4\% = 0.044$
$P = \frac{500}{0.044 \times 3} = \frac{500}{0.132} \approx 3787.88$
Step7: Solve for g. (Find I)
Convert rate to decimal: $4.4\% = 0.044$
Convert months to years: $t = \frac{30}{12} = 2.5$
$I = 3000 \times 0.044 \times 2.5$
$I = 3000 \times 0.11 = 330$
Step8: Solve for h. (Find r)
Rearrange formula: $r = \frac{I}{P \times t}$
Convert months to years: $t = \frac{30}{12} = 2.5$
$r = \frac{500}{P \times 2.5}$
Wait, correction: For h, $I=500$, $P=x$ (unknown), $r=3\%=0.03$, $t=30$ months $=2.5$ years.
Rearrange to find $P$: $P = \frac{I}{r \times t} = \frac{500}{0.03 \times 2.5} = \frac{500}{0.075} \approx 6666.67$
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
| Interest | Principal | Rate (percent) | Time |
|---|---|---|---|
| b. $\$179.38$ | $\$3,500$ | 4.1% | 15 months |
| c. $\$1,210.68$ | $\$20,100$ | 5.5% | 400 days |
| d. $\$100$ | $\$700$ | 13.04% | 400 days |
| e. $\$250$ | $\$3,000$ | $4\frac{3}{4}\%$ | 1.75 years |
| f. $\$500$ | $\$3,787.88$ | 4.4% | 3 years |
| g. $\$330.00$ | $\$3,000$ | 4.4% | 30 months |
| h. $\$500$ | $\$6,666.67$ | 3% | 30 months |