Question

12 the figure below shows square rstu on a coordinate plane. if the square is dilated using the rule (x, y)→(1/3x, 1/3y) with the origin as the center of dilation, what are the coordinates of vertex t of the dilated square rstu? a (4, 4) c (24, 24) b (36, 36) d (8, 8)

Explanation:

Step1: Identify original coordinates of T

From the graph, the coordinates of vertex T are (12, 12).

Step2: Apply dilation rule

The dilation rule is $(x,y)\to(\frac{1}{3}x,\frac{1}{3}y)$. Substitute $x = 12$ and $y = 12$ into the rule. For the x - coordinate of T': $\frac{1}{3}\times12 = 4$. For the y - coordinate of T': $\frac{1}{3}\times12 = 4$.

Answer:

A. (4, 4)