Question

12 formula 1 punto a gas balloon has a volume of 3.3 liters when the temperature is 12.9 °c and the pressure is 705.0 mm of mercury. what will its volume be, in l, at 24.8 °c and 728.2 mm of mercury pressure? express your answer with 1 decimal place. respuesta anterior siguiente

Explanation:

Step1: Convert temperatures to Kelvin

$T_1 = 12.9 + 273.15=286.05$ K, $T_2=24.8 + 273.15 = 297.95$ K

Step2: Apply the combined - gas law $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

Given $P_1 = 705.0$ mmHg, $V_1 = 3.3$ L, $P_2 = 728.2$ mmHg. We need to solve for $V_2$.
First, re - arrange the combined - gas law formula for $V_2$: $V_2=\frac{P_1V_1T_2}{T_1P_2}$

Step3: Substitute the values

$V_2=\frac{705.0\times3.3\times297.95}{286.05\times728.2}$
$V_2=\frac{705.0\times3.3\times297.95}{286.05\times728.2}=\frac{705.0\times3.3\times297.95}{208477.81}$
$V_2=\frac{696997.425}{208477.81}\approx3.3$ L

Answer:

$3.3$