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6(r + 1) = 12 r + 1 = 2 r = subtract 1 from both sides

Question

6(r + 1) = 12
r + 1 = 2
r =
subtract 1 from both sides

Explanation:

Step1: Analyze the equation \( r + 1 = 2 \)

We need to solve for \( r \). The operation suggested is to subtract 1 from both sides.

Step2: Subtract 1 from both sides

Subtract 1 from both sides of the equation \( r + 1 = 2 \). So we have \( r + 1 - 1 = 2 - 1 \).
Simplifying both sides, \( r = 1 \).

Answer:

For the first box (the operation), it's "Subtract 1 from both sides" (but since the dropdown is probably for the operation step, and then for \( r \), the value is 1. So the value of \( r \) is \( \boldsymbol{1} \).