Question

1. bailey will roll a number cube and flip a coin for a probability experiment. if bailey rolls the number cube once and flips the coin once, which list contains only the outcomes in which the number cube lands on a number greater than 4?

a 5, heads
5, tails
6, heads
6, tails
b 5, heads
6, tails
a
b
c 1, heads
1, tails
2, heads
2, tails
3, heads
3, tails
4, heads
4, tails
5, heads
5, tails
6, heads
6, tails
d 4, heads
4, tails
5, heads
5, tails
6, heads
6, tails

Explanation:

Step1: Identify numbers >4 on cube

A number cube has numbers 1 - 6. Numbers greater than 4 are 5, 6.

Step2: Analyze coin outcomes

A coin has 2 outcomes: Heads (H), Tails (T). So for 5 and 6, each pairs with H and T.

Step3: Evaluate options

• Option A: Includes (5,H), (5,T), (6,H), (6,T) – all valid (5,6 >4, paired with H/T).
• Option B: Missing (5,T) and (6,H)? No, wait, B has (5,H), (6,T) – incomplete. Wait, no: Wait, A has 4 outcomes, B has 2. Wait, no: Wait, numbers >4 are 5,6. Each has 2 coin outcomes, so total 4 outcomes: (5,H), (5,T), (6,H), (6,T). So Option A has all 4, Option B has 2 (missing (5,T) and (6,H)? Wait no, B is (5,H), (6,T) – no, that's wrong. Wait, no: Wait the problem says "list contains only the outcomes in which the number cube lands on a number greater than 4". So numbers must be >4 (5,6) and coin can be H or T. So possible outcomes: (5,H), (5,T), (6,H), (6,T). So Option A has these four, Option B has two, Option C has numbers ≤4, Option D has 4 (which is not >4). So Option A is correct.

Answer:

A. 5, Heads; 5, Tails; 6, Heads; 6, Tails