Question

13 ft.12 ft.13 ft.10 ft.10 ft.which diagram is a net for this prism?13 ft.10 ft.10 ft.10 ft.12 ft.12 ft.10 ft.13 ft.13 ft.10 ft.10 ft.12 ft.12 ft.10 ft.10 ft.13 ft.10 ft.10 ft.what is the surface area of the triangular prism?square feet

Explanation:

Step1: Identify correct net

The prism is a triangular prism with: 2 congruent triangular bases (base 10 ft, height 12 ft, side 13 ft) and 3 rectangular faces: two rectangles with dimensions 10 ft × 13 ft, one rectangle with dimensions 10 ft × 10 ft. The first diagram matches this (2 triangles, two 13×10 rectangles, one 10×10 rectangle).

Step2: Calculate area of triangular bases

Area of one triangle: $\frac{1}{2} \times 10 \times 12 = 60$ square feet.
Area of two triangles: $2 \times 60 = 120$ square feet.

Step3: Calculate area of rectangles

Area of two 13×10 rectangles: $2 \times (13 \times 10) = 260$ square feet.
Area of 10×10 rectangle: $10 \times 10 = 100$ square feet.
Total rectangle area: $260 + 100 = 360$ square feet.

Step4: Sum all areas

Total surface area = triangular area + rectangular area
<Expression>
$120 + 360 = 480$
</Expression>

Answer:

Correct net: The first (left) diagram
Surface area: 480 square feet