Question

1. if ∠5 = 4x + 20 and ∠6 = 2x + 40 are alternate exterior angles, what is the value of x?

a. 10
b. 15
c. 25
d. 30

Explanation:

Step1: Recall angle - property

Alternate exterior angles are equal. So \(4x + 20=2x + 40\).

Step2: Isolate x - terms

Subtract \(2x\) from both sides: \(4x-2x + 20=2x-2x + 40\), which simplifies to \(2x+20 = 40\).

Step3: Isolate the variable x

Subtract 20 from both sides: \(2x+20 - 20=40 - 20\), getting \(2x=20\).

Step4: Solve for x

Divide both sides by 2: \(\frac{2x}{2}=\frac{20}{2}\), so \(x = 10\).

Answer:

A. 10