Question

1. the coordinates of △pqr and its image are shown. describe the transformation.

p(-6, 0)→p(-6, 0)
q(2, -4)→q(2, 4)
r(-7, 5)→r(-7, -5)

Explanation:

Step1: Analyze coordinate changes

For point $P(-6,0)\to P'(-6,0)$, the $x$-coordinate remains the same and the $y$-coordinate remains the same. For point $Q(2, - 4)\to Q'(2,4)$, the $x$-coordinate is unchanged and the $y$-coordinate changes sign. For point $R(-7,5)\to R'(-7,-5)$, the $x$-coordinate is unchanged and the $y$-coordinate changes sign.

Step2: Identify transformation type

A transformation that keeps the $x$-coordinates the same and changes the sign of the $y$-coordinates is a reflection over the $x$-axis.

Answer:

Reflection over the $x$-axis.