QUESTION IMAGE
Question
- what is the scale factor of figure b to figure a?
- given the similar figures below, find the value of x.
- given figure abcd ~ figure ehgf, find ef.
- given δjkl ~ δmnl, find jk.
- a stop sign casts a shadow 8 feet long, while a school bus nearby casts a shadow 12 feet long. if the stop sign is 7 feet tall, how tall is the school bus?
- a 54 - foot tall office building casts a shadow that is 48 feet long. if mindy is 56 tall and standing nearby, find the length of her shadow.
a. $3\frac{3}{4}$ feet c. $4\frac{1}{3}$ feet
b. $4\frac{1}{2}$ feet d. $4\frac{8}{9}$ feet
use the diagram below to answer questions 24 - 25.
- which proportion could find x, the distance across griffin lake?
a. $\frac{64}{84}=\frac{x}{92}$ c. $\frac{64}{92}=\frac{84}{x}$
b. $\frac{x}{64}=\frac{84}{92}$ d. $\frac{84}{x}=\frac{92}{64}$
- find x.
Step1: Define scale factor (B to A)
Scale factor = $\frac{\text{Side of A}}{\text{Side of B}}$
Step2: Calculate using matching sides
$\text{Scale factor} = \frac{20}{5} = 4$
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Step1: Set up proportion for similar triangles
$\frac{x}{10} = \frac{28}{23}$
Step2: Solve for $x$
$x = 10 \times \frac{28}{23} = \frac{280}{23} \approx 12.17$
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Step1: Find scale factor (ABCD to EHGF)
$\text{Scale factor} = \frac{10}{15} = \frac{2}{3}$
Step2: Calculate $EF$
$EF = 18 \times \frac{2}{3} = 12$
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Step1: Find scale factor (JKL to MNL)
$\text{Scale factor} = \frac{24}{20} = \frac{6}{5}$
Step2: Calculate $JK$
$JK = 12 \times \frac{6}{5} = 14.4$
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Step1: Set up height-shadow proportion
$\frac{\text{Bus height}}{12} = \frac{7}{8}$
Step2: Solve for bus height
$\text{Bus height} = 12 \times \frac{7}{8} = 10.5$
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Step1: Convert height to feet: $5'6'' = 5.5$ ft
Step2: Set up proportion
$\frac{5.5}{54} = \frac{\text{Shadow length}}{48}$
Step3: Solve for shadow length
$\text{Shadow length} = 5.5 \times \frac{48}{54} = \frac{44}{9} = 4\frac{8}{9}$
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Step1: Identify correct proportion for similar triangles
Corresponding sides: $\frac{64}{84} = \frac{x}{92}$
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Step1: Solve the proportion for $x$
$x = 92 \times \frac{64}{84} = \frac{92 \times 16}{21} = \frac{1472}{21} \approx 70.09$
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- $4$
- $x = \frac{280}{23}$ or $\approx 12.17$
- $EF = 12$
- $JK = 14.4$
- $10.5$ feet
- D. $4\frac{8}{9}$ feet
- A. $\frac{64}{84} = \frac{x}{92}$
- $x = \frac{1472}{21}$ or $\approx 70.09$ feet