Question

1. (1.140) the candy jar has 3 chocolate bars, 1 lollipop, and 1 jawbreaker. if you pull out two candies without looking, what is the probability of getting a chocolate bar followed by a lollipop? (assume you dont put the first piece of candy back.) write your answer as a percent. a) 10% b) 15% c) 20% d) 25% e) 45%

Explanation:

Step1: Calculate total candies

There are $3 + 1+1=5$ candies initially.

Step2: Calculate probability of first - draw

The probability of drawing a chocolate bar first is $\frac{3}{5}$ since there are 3 chocolate bars out of 5 candies.

Step3: Calculate probability of second - draw

After drawing a chocolate bar, there are 4 candies left. The probability of drawing a lollipop second is $\frac{1}{4}$.

Step4: Calculate combined probability

By the multiplication rule for dependent events, the probability of getting a chocolate bar followed by a lollipop is $\frac{3}{5}\times\frac{1}{4}=\frac{3}{20}$.

Step5: Convert to percentage

$\frac{3}{20}\times100\% = 15\%$.

Answer:

b) 15%