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20) $30ab^{3}$, $20ab^{3}$ 22) 28, 14, 21 24) $10ba$, $20ba$, $28ba$ 26…

Question

  1. $30ab^{3}$, $20ab^{3}$
  2. 28, 14, 21
  3. $10ba$, $20ba$, $28ba$
  4. $28b^{2}$, $20ab^{3}$, $16b^{4}$

Explanation:

Response

Since the problem type (e.g., finding GCF, LCM, or something else) is not specified, I'll assume we are finding the greatest common factor (GCF) for each set as it's a common operation with such terms. Let's solve each sub - question:

Sub - question 20: For \(30ab^{3}\) and \(20ab^{3}\)

Step 1: Find GCF of coefficients

The coefficients are 30 and 20. The factors of 30 are \(1, 2, 3, 5, 6, 10, 15, 30\) and the factors of 20 are \(1, 2, 4, 5, 10, 20\). The greatest common factor of 30 and 20 is 10.

Step 2: Find GCF of variables

For the variable part, both terms have \(a\) (with exponent 1) and \(b^{3}\). So the variable part of the GCF is \(ab^{3}\).

Step 3: Combine coefficient and variable GCF

Multiply the coefficient GCF (10) with the variable GCF (\(ab^{3}\)) to get \(10ab^{3}\).

Step 1: List factors of 28

The factors of 28 are \(1, 2, 4, 7, 14, 28\).

Step 2: List factors of 14

The factors of 14 are \(1, 2, 7, 14\).

Step 3: List factors of 21

The factors of 21 are \(1, 3, 7, 21\).

Step 4: Identify common factors and GCF

The common factors of 28, 14, and 21 are 1 and 7. The greatest among them is 7.

Step 1: Find GCF of coefficients

The coefficients are 10, 20, and 28. The factors of 10 are \(1, 2, 5, 10\), factors of 20 are \(1, 2, 4, 5, 10, 20\), and factors of 28 are \(1, 2, 4, 7, 14, 28\). The greatest common factor of 10, 20, and 28 is 2.

Step 2: Find GCF of variables

All terms have \(ba\) (which is the same as \(ab\)). So the variable part of the GCF is \(ba\) (or \(ab\)).

Step 3: Combine coefficient and variable GCF

Multiply the coefficient GCF (2) with the variable GCF (\(ba\)) to get \(2ba\) (or \(2ab\)).

Answer:

\(10ab^{3}\)

Sub - question 22: For 28, 14, and 21