Question

20082y0 2 math grade 6
5-4: mathxl for school: practice & problem solving
part 1 of 2
the measurements of a circular object are given in the ratio table.
a. find the missing dimensions of other circular objects by completing the ratio table.
b. graph the pairs of values.
diameter, d 42 mm 301 mm
circumference, c 132 mm 198 mm
a. complete the ratio table.
diameter, d 42 mm 63 mm 301 mm
circumference, c 132 mm 198 mm 943 mm
(type whole numbers.)

Explanation:

Step1: Find the ratio constant

Calculate $\frac{C}{d}$: $\frac{132}{42} \approx 3.14$ (or $\frac{22}{7}$)

Step2: Solve for missing diameter

Rearrange ratio: $d = \frac{C}{3.14}$. For $C=198$ mm: $d = \frac{198}{3.14} \approx 63$ mm

Step3: Solve for missing circumference

Use $C = 3.14 \times d$. For $d=301$ mm: $C = 3.14 \times 301 \approx 943$ mm

Answer:

Completed ratio table:

Diameter, d	42 mm	63 mm	301 mm