Question

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during a washington capitals hockey game, a player hits a 0.16 kg puck giving it an initial velocity of 18.0 m/s. the puck takes 3.0 s to reach the other end of the ice rink. by the time the puck hits the wall it has slowed down to 15.0 m/s. the coefficient of kinetic friction between the rubber puck and the ice is, $mu_{k}=0.12$.
what is the average acceleration of the puck as it slides across the ice?
a
-1.0 m/s²
b
-9.8 m/s²

Explanation:

Step1: Recall acceleration formula

The formula for average acceleration is $a=\frac{v - u}{t}$, where $v$ is the final velocity, $u$ is the initial velocity and $t$ is the time - interval.

Step2: Identify given values

Given $u = 18.0\ m/s$, $v = 15.0\ m/s$, and $t=3.0\ s$.

Step3: Substitute values into formula

$a=\frac{15.0 - 18.0}{3.0}=\frac{- 3.0}{3.0}=-1.0\ m/s^{2}$

Answer:

A. $-1.0\ m/s^{2}$