Question

1. find m∠nab. c 60° a n 28x - 2 12x + 2 b

Explanation:

Step1: Use exterior - angle property of a triangle

The exterior - angle of a triangle is equal to the sum of the two non - adjacent interior angles. So, for \(\triangle ABC\) with exterior angle \(\angle NAB\), we have \(28x - 2=(12x + 2)+60\).

Step2: Solve the equation for \(x\)

First, simplify the right - hand side of the equation: \(28x-2 = 12x+62\). Then, subtract \(12x\) from both sides: \(28x-12x-2=12x - 12x+62\), which gives \(16x-2 = 62\). Next, add 2 to both sides: \(16x-2 + 2=62 + 2\), so \(16x=64\). Divide both sides by 16: \(x=\frac{64}{16}=4\).

Step3: Find the measure of \(\angle NAB\)

Substitute \(x = 4\) into the expression for \(\angle NAB\). \(\angle NAB=28x - 2\). So, \(\angle NAB=28\times4-2=112 - 2=110^{\circ}\).

Answer:

\(110^{\circ}\)