Question

1. if a 25kg tree limb falls on a roof and has a final kinetic energy of 20825j, what is the speed of the limb?

$12.91\frac{m}{s}$
$0\frac{m}{s}$
$166.6\frac{m}{s}$
$2.603\frac{m}{s}$

Explanation:

Step1: Recall kinetic energy formula

$KE = \frac{1}{2}mv^2$

Step2: Rearrange for velocity

$v = \sqrt{\frac{2KE}{m}}$

Step3: Substitute given values

$v = \sqrt{\frac{2 \times 2082.5}{25}}$

Step4: Calculate final velocity

$v = \sqrt{166.6} = 12.91$ $\frac{\text{m}}{\text{s}}$

Answer:

12.91 $\frac{\text{m}}{\text{s}}$