Question

f(x)=\frac{9}{5}(x - 273.15)+32
the function f gives the temperature, in degrees fahrenheit, that corresponds to a temperature of x kelvins. if a temperature increased by 13.30 kelvins, by how much did the temperature increase, in degrees fahrenheit?
a 23.94
b 55.94
c 467.73
d 499.73

Explanation:

Step1: Identify the rate of change

The function $F(x)=\frac{9}{5}(x - 273.15)+32$ is a linear function. The coefficient of $x$ in the linear - function represents the rate of change of $F$ with respect to $x$. The coefficient of $x$ is $\frac{9}{5}$.

Step2: Calculate the increase in Fahrenheit

We know that the increase in Kelvin is $\Delta x = 13.30$. To find the increase in Fahrenheit $\Delta F$, we multiply the increase in Kelvin by the rate of change of $F$ with respect to $x$. So, $\Delta F=\frac{9}{5}\times13.30$.
$\Delta F = 1.8\times13.30=23.94$.

Answer:

A. 23.94