Question

1. determine the rotational inertia of a hoop with a mass of 6 kg and a radius of 0.75 m. 1.35 kg·m² 3.375 kg·m² 1.69 kg·m² 0.68 kg·m²

Explanation:

Step1: Recall hoop inertia formula

The rotational inertia of a hoop is $I = MR^2$, where $M$ is mass, $R$ is radius.

Step2: Substitute given values

$M=6\ \text{kg}$, $R=0.75\ \text{m}$, so $I = 6\times(0.75)^2$

Step3: Calculate the result

First compute $(0.75)^2 = 0.5625$, then $6\times0.5625 = 3.375$
Final expression: $I=3.375\ \text{kg·m}^2$

Answer:

3.375 kg·m²