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29. match each point on the number line to one number in the table belo…

Question

  1. match each point on the number line to one number in the table below. not all numbers are represented on the number line. (3 points) \\(\sqrt{17}\\) \\(\sqrt{0.81}\\) \\(\sqrt{\frac{49}{4}}\\) \\(\sqrt{\frac{1}{9}}\\) \\(\sqrt{24}\\) \\(\sqrt{34}\\) \\(\sqrt{1.21}\\) \\(\sqrt{\frac{81}{16}}\\)

Explanation:

Response

To solve this, we first simplify each square root:

  • $\boldsymbol{\sqrt{17}} \approx 4.123$ (between 4 and 5)
  • $\boldsymbol{\sqrt{0.81}} = 0.9$ (close to 1, left of 1)
  • $\boldsymbol{\sqrt{\frac{49}{4}}} = \frac{7}{2} = 3.5$ (between 3 and 4)
  • $\boldsymbol{\sqrt{\frac{1}{9}}} = \frac{1}{3} \approx 0.333$ (close to 0, right of 0)
  • $\boldsymbol{\sqrt{24}} \approx 4.899$ (between 4 and 5, closer to 5)
  • $\boldsymbol{\sqrt{34}} \approx 5.831$ (close to 6)
  • $\boldsymbol{\sqrt{1.21}} = 1.1$ (close to 1, right of 1)
  • $\boldsymbol{\sqrt{\frac{81}{16}}} = \frac{9}{4} = 2.25$ (between 2 and 3)

Now match to the number line points:

  • Point F (close to 0): $\boldsymbol{\sqrt{\frac{1}{9}}}$ (≈0.333)
  • Point B (close to 1, left of 1): $\boldsymbol{\sqrt{0.81}}$ (0.9)
  • Point A (between 2 and 3): $\boldsymbol{\sqrt{\frac{81}{16}}}$ (2.25)
  • Point C (between 3 and 4): $\boldsymbol{\sqrt{\frac{49}{4}}}$ (3.5)
  • Point E (at 4): Wait, E is at 4? Wait, no—wait, E is on 4? Wait, the number line: F (0 -1), B (near 1), A (2 -3), C (3 -4), E (at 4), D (near 6). Wait, $\sqrt{17} \approx 4.123$ (so E? Wait, E is at 4, but $\sqrt{17} \approx 4.123$ is just right of 4. Wait, maybe:
  • Point E (right of 4): $\boldsymbol{\sqrt{17}}$ (≈4.123)
  • Point D (near 6): $\boldsymbol{\sqrt{34}}$ (≈5.831)
  • Point C (3 -4): $\boldsymbol{\sqrt{\frac{49}{4}}}$ (3.5)
  • Point A (2 -3): $\boldsymbol{\sqrt{\frac{81}{16}}}$ (2.25)
  • Point B (near 1, right of 1): $\boldsymbol{\sqrt{1.21}}$ (1.1)
  • Point F (near 0): $\boldsymbol{\sqrt{\frac{1}{9}}}$ (≈0.333)
  • Point E (at 4, right of 4): $\boldsymbol{\sqrt{17}}$ (≈4.123)
  • Point D (near 6): $\boldsymbol{\sqrt{34}}$ (≈5.831)
  • Point C (3 -4): $\boldsymbol{\sqrt{\frac{49}{4}}}$ (3.5)
  • Point A (2 -3): $\boldsymbol{\sqrt{\frac{81}{16}}}$ (2.25)
  • Point B (near 1, left of 1): $\boldsymbol{\sqrt{0.81}}$ (0.9)
  • Point F (near 0): $\boldsymbol{\sqrt{\frac{1}{9}}}$ (≈0.333)

Wait, let’s recheck:

  • F: closest to 0 → $\sqrt{\frac{1}{9}}$ (≈0.333)
  • B: near 1, left of 1 → $\sqrt{0.81}$ (0.9)
  • A: between 2 and 3 → $\sqrt{\frac{81}{16}}$ (2.25)
  • C: between 3 and 4 → $\sqrt{\frac{49}{4}}$ (3.5)
  • E: at 4, but $\sqrt{17} \approx 4.123$ (so E is at 4, but $\sqrt{17}$ is just right of 4 → E: $\sqrt{17}$
  • D: near 6 → $\sqrt{34}$ (≈5.831)
  • Wait, $\sqrt{24} \approx 4.899$ (between 4 and 5, closer to 5) → so maybe E is $\sqrt{17}$ (≈4.123) and $\sqrt{24}$ (≈4.899) is between E and D? Wait, the number line: E is at 4, then next is 5, then D at 6. So:
  • E: $\sqrt{17}$ (≈4.123, right of 4)
  • Between E and D (4 -5): $\sqrt{24}$ (≈4.899)
  • D: $\sqrt{34}$ (≈5.831, near 6)

Let’s correct:

  • F: $\sqrt{\frac{1}{9}}$ (≈0.333)
  • B: $\sqrt{0.81}$ (0.9)
  • A: $\sqrt{\frac{81}{16}}$ (2.25)
  • C: $\sqrt{\frac{49}{4}}$ (3.5)
  • E: $\sqrt{17}$ (≈4.123)
  • D: $\sqrt{34}$ (≈5.831)
  • Wait, what about $\sqrt{1.21}$ (1.1)? Oh, Point B is near 1, left of 1 (0.9), and $\sqrt{1.21}$ (1.1) is right of 1. Wait, the number line: B is at the dot near 1 (before 1? Wait, the number line shows B at the dot before 1? Wait, the number line: 0 --- F --- B --- 1 --- 2 --- A --- 3 --- C --- 4 --- E --- 5 --- D --- 6. So B is between 0 and 1, near 1? Wait, $\sqrt{0.81}=0.9$ (left of 1), $\sqrt{1.21}=1.1$ (right of 1). So:
  • F: $\sqrt{\frac{1}{9}}$ (≈0.333)
  • B: $\sqrt{0.81}$ (0.9) (left of 1)
  • Then between B and 1: maybe $\sqrt{1.21}$ (1.1) is right of 1, but the number line has B at the dot before 1, then 1, then 2. Wait, maybe the problem’s table has 8 numbe…

Answer:

To solve this, we first simplify each square root:

  • $\boldsymbol{\sqrt{17}} \approx 4.123$ (between 4 and 5)
  • $\boldsymbol{\sqrt{0.81}} = 0.9$ (close to 1, left of 1)
  • $\boldsymbol{\sqrt{\frac{49}{4}}} = \frac{7}{2} = 3.5$ (between 3 and 4)
  • $\boldsymbol{\sqrt{\frac{1}{9}}} = \frac{1}{3} \approx 0.333$ (close to 0, right of 0)
  • $\boldsymbol{\sqrt{24}} \approx 4.899$ (between 4 and 5, closer to 5)
  • $\boldsymbol{\sqrt{34}} \approx 5.831$ (close to 6)
  • $\boldsymbol{\sqrt{1.21}} = 1.1$ (close to 1, right of 1)
  • $\boldsymbol{\sqrt{\frac{81}{16}}} = \frac{9}{4} = 2.25$ (between 2 and 3)

Now match to the number line points:

  • Point F (close to 0): $\boldsymbol{\sqrt{\frac{1}{9}}}$ (≈0.333)
  • Point B (close to 1, left of 1): $\boldsymbol{\sqrt{0.81}}$ (0.9)
  • Point A (between 2 and 3): $\boldsymbol{\sqrt{\frac{81}{16}}}$ (2.25)
  • Point C (between 3 and 4): $\boldsymbol{\sqrt{\frac{49}{4}}}$ (3.5)
  • Point E (at 4): Wait, E is at 4? Wait, no—wait, E is on 4? Wait, the number line: F (0 -1), B (near 1), A (2 -3), C (3 -4), E (at 4), D (near 6). Wait, $\sqrt{17} \approx 4.123$ (so E? Wait, E is at 4, but $\sqrt{17} \approx 4.123$ is just right of 4. Wait, maybe:
  • Point E (right of 4): $\boldsymbol{\sqrt{17}}$ (≈4.123)
  • Point D (near 6): $\boldsymbol{\sqrt{34}}$ (≈5.831)
  • Point C (3 -4): $\boldsymbol{\sqrt{\frac{49}{4}}}$ (3.5)
  • Point A (2 -3): $\boldsymbol{\sqrt{\frac{81}{16}}}$ (2.25)
  • Point B (near 1, right of 1): $\boldsymbol{\sqrt{1.21}}$ (1.1)
  • Point F (near 0): $\boldsymbol{\sqrt{\frac{1}{9}}}$ (≈0.333)
  • Point E (at 4, right of 4): $\boldsymbol{\sqrt{17}}$ (≈4.123)
  • Point D (near 6): $\boldsymbol{\sqrt{34}}$ (≈5.831)
  • Point C (3 -4): $\boldsymbol{\sqrt{\frac{49}{4}}}$ (3.5)
  • Point A (2 -3): $\boldsymbol{\sqrt{\frac{81}{16}}}$ (2.25)
  • Point B (near 1, left of 1): $\boldsymbol{\sqrt{0.81}}$ (0.9)
  • Point F (near 0): $\boldsymbol{\sqrt{\frac{1}{9}}}$ (≈0.333)

Wait, let’s recheck:

  • F: closest to 0 → $\sqrt{\frac{1}{9}}$ (≈0.333)
  • B: near 1, left of 1 → $\sqrt{0.81}$ (0.9)
  • A: between 2 and 3 → $\sqrt{\frac{81}{16}}$ (2.25)
  • C: between 3 and 4 → $\sqrt{\frac{49}{4}}$ (3.5)
  • E: at 4, but $\sqrt{17} \approx 4.123$ (so E is at 4, but $\sqrt{17}$ is just right of 4 → E: $\sqrt{17}$
  • D: near 6 → $\sqrt{34}$ (≈5.831)
  • Wait, $\sqrt{24} \approx 4.899$ (between 4 and 5, closer to 5) → so maybe E is $\sqrt{17}$ (≈4.123) and $\sqrt{24}$ (≈4.899) is between E and D? Wait, the number line: E is at 4, then next is 5, then D at 6. So:
  • E: $\sqrt{17}$ (≈4.123, right of 4)
  • Between E and D (4 -5): $\sqrt{24}$ (≈4.899)
  • D: $\sqrt{34}$ (≈5.831, near 6)

Let’s correct:

  • F: $\sqrt{\frac{1}{9}}$ (≈0.333)
  • B: $\sqrt{0.81}$ (0.9)
  • A: $\sqrt{\frac{81}{16}}$ (2.25)
  • C: $\sqrt{\frac{49}{4}}$ (3.5)
  • E: $\sqrt{17}$ (≈4.123)
  • D: $\sqrt{34}$ (≈5.831)
  • Wait, what about $\sqrt{1.21}$ (1.1)? Oh, Point B is near 1, left of 1 (0.9), and $\sqrt{1.21}$ (1.1) is right of 1. Wait, the number line: B is at the dot near 1 (before 1? Wait, the number line shows B at the dot before 1? Wait, the number line: 0 --- F --- B --- 1 --- 2 --- A --- 3 --- C --- 4 --- E --- 5 --- D --- 6. So B is between 0 and 1, near 1? Wait, $\sqrt{0.81}=0.9$ (left of 1), $\sqrt{1.21}=1.1$ (right of 1). So:
  • F: $\sqrt{\frac{1}{9}}$ (≈0.333)
  • B: $\sqrt{0.81}$ (0.9) (left of 1)
  • Then between B and 1: maybe $\sqrt{1.21}$ (1.1) is right of 1, but the number line has B at the dot before 1, then 1, then 2. Wait, maybe the problem’s table has 8 numbers, and 6 points? Wait, the problem says “match each point” (F, B, A, C, E, D: 6 points) to “one number in the table” (8 numbers). So we pick 6 numbers.

Final matches (most logical):

  • F: $\boldsymbol{\sqrt{\frac{1}{9}}}$ (≈0.333, closest to 0)
  • B: $\boldsymbol{\sqrt{0.81}}$ (0.9, close to 1, left of 1)
  • A: $\boldsymbol{\sqrt{\frac{81}{16}}}$ (2.25, between 2 and 3)
  • C: $\boldsymbol{\sqrt{\frac{49}{4}}}$ (3.5, between 3 and 4)
  • E: $\boldsymbol{\sqrt{17}}$ (≈4.123, right of 4)
  • D: $\boldsymbol{\sqrt{34}}$ (≈5.831, close to 6)

(Note: $\sqrt{1.21}=1.1$ and $\sqrt{24}≈4.899$ are extra, as we only need 6 matches.)