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(-2v² + 3v - 4) - (7v² + v + 6)

Question

(-2v² + 3v - 4) - (7v² + v + 6)

Explanation:

Step1: Remove parentheses

To remove the parentheses, we distribute the negative sign to each term inside the second parentheses:
\((-2v^{2}+3v - 4)-(7v^{2}+v + 6)=-2v^{2}+3v-4 - 7v^{2}-v - 6\)

Step2: Combine like terms

  • For the \(v^{2}\) terms: \(-2v^{2}-7v^{2}=-9v^{2}\)
  • For the \(v\) terms: \(3v - v = 2v\)
  • For the constant terms: \(-4-6=-10\)

Putting it all together, we get: \(-9v^{2}+2v - 10\)

Answer:

\(-9v^{2}+2v - 10\)