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g(x)=2x - 10 h(x)=-\frac{2}{3}x j(x)=\frac{2}{3}x + 10 study the linear…

Question

g(x)=2x - 10
h(x)=-\frac{2}{3}x
j(x)=\frac{2}{3}x + 10
study the linear functions graphed to complete each statement.
consider the two lines represented by the functions f(x)=2x and g(x)=2x - 10. to determine where the two lines intersect, you can set both functions equal to each other and solve.
2x=2x - 10
2x-
i
=-10
0=

the equation 2x=2x - 10
. this means that the two
lines described by the functions f(x)=2x and g(x)=2x - 10

Explanation:

Step1: Subtract 2x from both sides

$2x-2x=2x - 10-2x$

Step2: Simplify the equation

$0=- 10$
The equation $2x = 2x-10$ has no solution. This means that the two lines described by the functions $f(x)=2x$ and $g(x)=2x - 10$ are parallel (since they have the same slope of 2 and different y - intercepts).

Answer:

The first blank should be filled with $2x$, the second blank should be filled with $-10$, and the third blank should be filled with "has no solution", and the fourth blank should be filled with "are parallel".