Question

4 \

$$\begin{cases} 2x + y = 10 \\\\ 3x + 5y = 8 \\end{cases}$$

Explanation:

Step1: Isolate y from first equation

$y = 10 - 2x$

Step2: Substitute y into second equation

$3x + 5(10 - 2x) = 8$

Step3: Simplify to solve for x

$3x + 50 - 10x = 8$
$-7x = 8 - 50$
$-7x = -42$
$x = \frac{-42}{-7} = 6$

Step4: Substitute x=6 into y=10-2x

$y = 10 - 2(6) = 10 - 12 = -2$

Answer:

$x=6$, $y=-2$