Question

1. what is the total number of joules required to melt 100 grams of ice at 0°c to liquid water at 0°c? a. 5,400 j b. 33,400 j c. 8,000 j d. 226,000 j

Explanation:

Step1: Recall heat - of - fusion formula

The heat required to change a substance from solid to liquid (phase - change) is given by $Q = m\times\Delta H_f$, where $m$ is the mass of the substance and $\Delta H_f$ is the heat of fusion. For water, the heat of fusion $\Delta H_f=334\ J/g$.

Step2: Substitute values

We have $m = 100\ g$ and $\Delta H_f = 334\ J/g$. So, $Q=100\ g\times334\ J/g$.

Step3: Calculate the heat

$Q = 33400\ J$.

Answer:

B. 33,400 J