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b 34° 126° x°

Question

b 34° 126° x°

Explanation:

Step1: Use angle - sum property of a triangle - like figure

The angles in the figure can be considered in terms of the angles formed by parallel lines and a transversal. The sum of the interior angles of the non - standard polygon formed by the intersection of the lines is related to the given angles. We know that the sum of angles around a point is 360°. Also, when considering the angles formed by parallel lines and a transversal, we can find the missing angle.
Let's assume the angles are related in a way that we can use the fact that the sum of angles in a polygon - like structure formed by the intersection of lines.
We know that the sum of the three angles shown (34°, x°, 126°) and the angle adjacent to 34° (which is 180 - 34=146°) and the angle adjacent to 126° (which is 180 - 126 = 54°) around the intersection points of the lines should satisfy the angle - sum relations.
However, a simpler way is to use the fact that if we consider the angles formed by parallel lines and a transversal, we can see that the sum of the three given non - supplementary angles in the figure should be 180°.
So, 34°+x°+126° = 180°.

Step2: Solve for x

We have the equation 34 + x+126=180.
Combining like terms on the left - hand side: (34 + 126)+x=180.
160+x=180.
Subtract 160 from both sides: x=180 - 160.
x = 20.

Answer:

20