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39. $f = \\frac{9}{5}c + 32$ for $c$ (celsius to fahrenheit) 40. $c = \…

Question

  1. $f = \frac{9}{5}c + 32$ for $c$ (celsius to fahrenheit)
  2. $c = \frac{5}{9}(f - 32)$ for $f$ (fahrenheit to celsius)
  3. calculate the body mass index of a person who is 6 feet 1 inch tall with a weight of 170 pounds. what is this person’s weight status? (see example 4 in section 1 - 2.)
  4. what are the bmi and weight status of a person who is 5 feet tall and weighs 160 pounds? (see example 4 in section 1 - 2.)

Explanation:

Step1: Convert height to inches

6 feet 1 inch = 6*12 + 1 = 73 inches.

Step2: Convert height to meters

1 inch = 0.0254 meters, so 73 inches = 73*0.0254 = 1.8542 meters.

Step3: Convert weight to kilograms

1 pound = 0.453592 kilograms, so 170 pounds = 170*0.453592 = 77.11064 kilograms.

Step4: Calculate BMI

BMI formula is $BMI=\frac{weight(kg)}{height(m)^2}$, so $BMI=\frac{77.11064}{1.8542^2}\approx22.3$.

Step5: Determine weight - status

A BMI between 18.5 and 24.9 is considered normal. So the weight - status is normal.

for question 42:

Step1: Convert height to inches

5 feet = 5*12 = 60 inches.

Step2: Convert height to meters

1 inch = 0.0254 meters, so 60 inches = 60*0.0254 = 1.524 meters.

Step3: Convert weight to kilograms

1 pound = 0.453592 kilograms, so 160 pounds = 160*0.453592 = 72.57472 kilograms.

Step4: Calculate BMI

Using the formula $BMI = \frac{weight(kg)}{height(m)^2}$, we have $BMI=\frac{72.57472}{1.524^2}\approx31.2$.

Step5: Determine weight - status

A BMI of 30 or higher is considered obese. So the weight - status is obese.

Answer:

The BMI is approximately 22.3 and the weight - status is normal.