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3a by how much does the range of the data increase after making this co…

Question

3a by how much does the range of the data increase after making this correction? increase in range = enter your next step here

Explanation:

Step1: Find original range

Assume original max is 49, original min is, say, let's see the left whisker. Wait, the correction: before correction, maybe min was higher? Wait, the x - axis has 4, 39, 44, 49. So after correction, min is 4, before correction, min was, say, 39? Wait, the boxplot: original min (before correction) is the left end of the left whisker, maybe 39? And after correction, min is 4. Max is still 49? Wait, range is max - min.

Original range (before correction): max - original min. Let's assume original min is 39, max is 49. So original range = 49 - 39 = 10.

After correction, min is 4, max is 49. So new range = 49 - 4 = 45.

Step2: Calculate increase

Increase in range = new range - original range = 45 - 10 = 35? Wait, no, wait. Wait, maybe original min was, let's check the boxplot. The left whisker before correction: the left end of the left whisker is at 39? And after correction, the min is 4. So original range: max (49) - original min (39) = 10. New range: 49 - 4 = 45. Then increase is 45 - 10 = 35? Wait, no, maybe I misread. Wait, the x - axis: the first mark is 4, then 39, 44, 49. So before correction, the minimum value was, say, 39 (the left end of the left whisker), and after correction, the minimum is 4. The maximum remains 49 (right end of right whisker).

So original range: \( 49 - 39 = 10 \)

New range: \( 49 - 4 = 45 \)

Increase in range: \( 45 - 10 = 35 \)

Wait, but maybe the original max was different? No, the right whisker end is at 49. So the correction is changing the minimum from 39 to 4. So range increase is (49 - 4) - (49 - 39) = 45 - 10 = 35.

Answer:

35