Question

a. 3v
b. 2v
c. 1.5v
d. zero

1. a bomb travelling in parabolic path under the effect of gravity, explodes in mid air.

the centre of mass of the fragments will
a. move in irregular path
b. move vertically downward
c. move in parabolic path, the unexploded bomb will have travelled.
d. move vertically upward and then vertically downward

1. caste study -ii

first law of thermodynamics
heat and work are two modes of energy transfer to a system. heat is the energy transfer
arising due to temperature difference between the system and the surroundings. work
is energy transfer brought about by other means, such as moving poston of a cylinder
containing the gas, by raising or lowering some weight connected to it. according to
the first law of thermodynamics, if some heat is supplied to a system which is capable
of doing work, then the quantity of heat aborded by the system will be equal to the
sum of the increase in its internal energy and the external work doen by the system on
the surroundings. i.e. $\delta q = \delta u + \delta w$.

1. first law of thermodynamic is based on

a. conservation of energy
b. conservation of mass
c. conservation of momentum
d. conservation of charge

1. $\delta u + \delta w = 0$ is valid for

a. adiabatic process
b. isobaric process
c. isothermal process
d. isochoric process

1. which of the following parameter cloes not characterize the thermodynamic state of

matter?
a. temperature
b. pressure
c. work
d. volume

1. specific heat of a gas for an isothermal process is

a. infinity
b. zero
c. 4
d. 2
section - e

1. a. a projectile is fired with a velocity u making an angle $\theta$ with the horizontal. derive an

expressions for.
ii. maximum height

Explanation:

Step1: Q4 (Parabola Bomb)

The internal explosion forces are internal to the system (bomb fragments), so external gravity is the only net external force. The center of mass continues the original parabolic path of the unexploded bomb.

Step2: Q30.1 (First Law Basis)

The first law $\Delta Q = \Delta U + \Delta W$ restates that energy is conserved: energy input (heat) equals energy change (internal energy) plus energy output (work).

Step3: Q30.2 (Adiabatic Condition)

An adiabatic process has no heat transfer, so $\Delta Q = 0$. Substitute into first law: $0 = \Delta U + \Delta W \implies \Delta U + \Delta W = 0$.

Step4: Q30.3 (Thermodynamic State Parameter)

Temperature, pressure, and volume are state properties (depend only on current state). Work is a path function (depends on how the system changes state), so it does not characterize the state.

Step5: Q30.4 (Isothermal Specific Heat)

For isothermal processes, $\Delta T = 0$. Specific heat $c = \frac{Q}{m\Delta T}$, so $\Delta T = 0$ makes $c$ infinite.

Answer:

1. c. move in parabolic path, the unexploded bomb will have travelled.

30.1. a. conservation of energy
30.2. a. adiabatic process
30.3. c. work
30.4. a. infinity