Question

2/4-2/13 math 8: term 3 homework #2due friday! name:1. solve. $2(3y + 4) = -46$2. solve. $2(3x - 5) = -46$3. solve for $x$:$3x + 6 = 4x - 1$4. solve for $x$:$5x - 5 = 10x + 40$5. what value of $x$ makes the equation below true?$5x - 2 = 48$a. 10 b. 18 c. 20 d. 486. what value of $z$ makes the equation below true?$4z + 6 = 10$a. 1 b. 6 c. 15 d. 19

Explanation:

Step1: Expand left side

$2(3y+4)=6y+8$

Step2: Isolate variable term

$6y = -46 - 8$
$6y = -54$

Step3: Solve for $y$

$y = \frac{-54}{6} = -9$

---

Step1: Expand left side

$2(3x-5)=6x-10$

Step2: Isolate variable term

$6x = -46 + 10$
$6x = -36$

Step3: Solve for $x$

$x = \frac{-36}{6} = -6$

---

Step1: Move $x$ terms to one side

$3x - 4x = -1 - 6$

Step2: Simplify both sides

$-x = -7$

Step3: Solve for $x$

$x = 7$

---

Step1: Move $x$ terms to one side

$5x - 10x = 40 + 5$

Step2: Simplify both sides

$-5x = 45$

Step3: Solve for $x$

$x = \frac{45}{-5} = -9$

---

Step1: Isolate variable term

$5x = 48 + 2$
$5x = 50$

Step2: Solve for $x$

$x = \frac{50}{5} = 10$

---

Step1: Isolate variable term

$4z = 10 - 6$
$4z = 4$

Step2: Solve for $z$

$z = \frac{4}{4} = 1$

Answer:

1. $y=-9$
2. $x=-6$
3. $x=7$
4. $x=-9$
5. A. 10
6. A. 1