Question

1. a city is planning to place a 22-foot-high statue in a local park. the artist who earned the commission is working from a model that is 18 inches high. a feature on the model measure 3 inches across. how large will the feature on the completed statue be? a. 2.45 feet b. 3.67 feet c. 4.00 feet d. 4.33 feet

Explanation:

Question 44

Step1: Convert units to be consistent. The statue height is 22 feet, which is \( 22\times12 = 264 \) inches. The model height is 18 inches.

Step2: Set up a proportion. Let \( x \) be the size of the feature on the statue (in inches). The proportion is \( \frac{18}{264}=\frac{3}{x} \).

Step3: Cross - multiply: \( 18x = 264\times3 \).

Step4: Solve for \( x \): \( x=\frac{264\times3}{18}=\frac{792}{18} = 44 \) inches.

Step5: Convert inches to feet. Since 1 foot = 12 inches, \( x=\frac{44}{12}\approx3.67 \) feet.

Step1: Recall the formula \( d = vt \), where \( d \) is distance, \( v \) is velocity, and \( t \) is time.

Step2: The velocity \( v = 75 \) miles per hour, and the time \( t = 1 \) minute. Since 1 hour = 60 minutes, \( t=\frac{1}{60} \) hours.

Step3: Substitute into the formula: \( d=75\times\frac{1}{60}=\frac{75}{60}=1.25 \) miles. (If we want to convert to other units, but the question doesn't specify, so in miles it's 1.25, or if in feet: 1 mile = 5280 feet, \( 1.25\times5280 = 6600 \) feet)

Answer:

B. 3.67 feet

Question 45