Question

1. une planche à roulettes coûte 1$ de plus que celle dun autre modèle. la somme de leurs prix est de 145$. combien coûte chacune de ces planches à roulettes?

Explanation:

Step1: Define variables

Let the price of the cheaper skateboard be \( x \) dollars. Then the price of the more expensive one is \( x + 1 \) dollars.

Step2: Set up the equation

The sum of their prices is 145 dollars, so we have the equation \( x+(x + 1)=145 \).

Step3: Solve the equation

Simplify the left side: \( 2x+1 = 145 \). Subtract 1 from both sides: \( 2x=145 - 1=144 \). Then divide both sides by 2: \( x=\frac{144}{2}=72 \).

Step4: Find the prices

The cheaper skateboard is \( x = 72 \) dollars, and the more expensive one is \( x + 1=72 + 1 = 73 \) dollars.

Answer:

The cheaper skateboard costs 72 dollars and the more expensive one costs 73 dollars.