Question

is (-5, -1) a solution to this system of equatic
y = -2x - 9
y = -x - 6

yes no

Explanation:

Step1: Check first equation

Substitute \( x = -5 \), \( y = -1 \) into \( y = -2x - 9 \).
Right - hand side: \( -2\times(-5)-9 = 10 - 9 = 1 \).
Left - hand side: \( y=-1 \). Since \( -1
eq1 \), we can already tell that \((-5, -1)\) is not a solution. But we can also check the second equation for completeness.

Step2: Check second equation

Substitute \( x = -5 \), \( y = -1 \) into \( y=-x - 6 \).
Right - hand side: \(-(-5)-6=5 - 6=-1\). Left - hand side: \( y = -1 \). Although it satisfies the second equation, it does not satisfy the first equation. For a point to be a solution to a system of equations, it must satisfy all the equations in the system.

Answer:

no