QUESTION IMAGE
Question
- ((a - 6)^2)\\4. ((5p + 2)^2)\\6. ((-12 - n)^2)\\8. ((0.5x - 0.7y)^2)\polynomial that represents the area of the square.\\10. \\(\
$$\begin{tikzpicture}scale=0.5\\draw (0,0) rectangle (2,2);\\draw (0,1) -- (2,1);\\draw (1,0) -- (1,2);\\filllightblue (0,1) rectangle (1,2);\\filllightblue (1,1) rectangle (2,2);\\filllightgreen (0,0) rectangle (1,1);\\filllightgreen (1,0) rectangle (2,1);\\fillyellow (0.5,0.5) rectangle (1.5,1.5);\
ode at (0.5,1.5) above {x};\
ode at (1.5,1.5) above {7};\
ode at (2.5,1.5) above {x};\
ode at (0.5,0.5) left {x};\
ode at (0.5,-0.5) below {7};\
ode at (0.5,-1.5) below {x};\\end{tikzpicture}$$
\\12. \\(\
$$\begin{tikzpicture}scale=0.5\\draw (0,0) rectangle (2,2);\\drawred (0,0.5) -- (2,0.5);\\drawred (0,1.5) -- (2,1.5);\\drawred (0.5,0) -- (0.5,2);\\drawred (1.5,0) -- (1.5,2);\\filllightblue (0,0) rectangle (2,2);\
ode at (1,1) {4c + 4d};\\end{tikzpicture}$$
\le 2.)\\14. ((m + 6)(m - 6))\\16. ((2k - 4)(2k + 4))\\18. ((2.5 + 3a)(2.5 - 3a))\\20. ((7m + 8n)(7m - 8n))\\(2n)
Response
Let's solve these problems one by one using the perfect square formula \((a\pm b)^2 = a^2\pm 2ab + b^2\) and the difference of squares formula \((a + b)(a - b)=a^2 - b^2\).
Problem 2: \((a - 6)^2\)
Step 1: Apply the perfect square formula \((x-y)^2=x^2-2xy + y^2\), where \(x = a\) and \(y=6\)
\((a - 6)^2=a^2-2\times a\times6+6^2\)
Step 2: Simplify the expression
\(a^2-12a + 36\)
Step 1: Apply the perfect square formula \((x + y)^2=x^2+2xy + y^2\), where \(x = 5p\) and \(y = 2\)
\((5p+2)^2=(5p)^2+2\times(5p)\times2+2^2\)
Step 2: Simplify the expression
\(25p^2 + 20p+4\)
Step 1: Rewrite \((-12 - n)^2\) as \([-(12 + n)]^2=(12 + n)^2\) (since \((-a)^2=a^2\))
Step 2: Apply the perfect square formula \((x + y)^2=x^2+2xy + y^2\), where \(x = 12\) and \(y=n\)
\((12 + n)^2=12^2+2\times12\times n+n^2\)
Step 3: Simplify the expression
\(144+24n + n^2=n^2+24n + 144\)
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\(a^2-12a + 36\)