Question

(5p²+5p-26)÷(p+3) 5p-10, r 4 5p-13, r 8 5p-10, r 5 5p-12, r 1

Explanation:

Step1: Divide leading terms

$\frac{5p^2}{p}=5p$

Step2: Multiply divisor by 5p

$5p(p+3)=5p^2+15p$

Step3: Subtract from dividend

$(5p^2+5p-26)-(5p^2+15p)=-10p-26$

Step4: Divide new leading term

$\frac{-10p}{p}=-10$

Step5: Multiply divisor by -10

$-10(p+3)=-10p-30$

Step6: Subtract to find remainder

$(-10p-26)-(-10p-30)=5$

Step7: Combine quotient and remainder

Quotient: $5p-10$, Remainder: 5

Answer:

5p-10, R 5