Question

1. (\frac{1}{3}n^{3}(6n - 9p + 18np^{4}) =)

Explanation:

Step1: Distribute the monomial

$\frac{1}{3}n^3 \cdot 6n - \frac{1}{3}n^3 \cdot 9p + \frac{1}{3}n^3 \cdot 18np^4$

Step2: Simplify each term

$\frac{6}{3}n^{3+1} - \frac{9}{3}n^3p + \frac{18}{3}n^{3+1}p^4$

Step3: Compute coefficients and exponents

$2n^4 - 3n^3p + 6n^4p^4$

Answer:

$2n^4 - 3n^3p + 6n^4p^4$