Question

f(x) = x² - 6x + 8 find the zeros of the function x = 2 and x = 4 x = -2 and x = -4 x = -2 and x = 4 x = 2 and x = -4

Explanation:

Step1: Set function equal to 0

$x^2 - 6x + 8 = 0$

Step2: Factor the quadratic

$(x-2)(x-4) = 0$

Step3: Solve for x

Set each factor to 0:
$x-2=0 \implies x=2$
$x-4=0 \implies x=4$

Answer:

x = 2 and x = 4