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70 m, 40 m, 30 m, 60 m (with a diagram of a composite figure including …

Question

70 m, 40 m, 30 m, 60 m (with a diagram of a composite figure including a yellow triangle, red rectangle, and green triangle)

Explanation:

Step1: Identify the shapes

The figure is composed of a yellow triangle, a red rectangle, and a green triangle. We can calculate the area of each shape and then sum them up.

Step2: Area of yellow triangle

The formula for the area of a triangle is $\frac{1}{2} \times base \times height$. The base of the yellow triangle is $30\ m$ and the height is $40\ m$. So its area is $\frac{1}{2} \times 30 \times 40$.
$\frac{1}{2} \times 30 \times 40 = 15 \times 40 = 600\ m^2$

Step3: Area of red rectangle

The formula for the area of a rectangle is $length \times width$. The length is $70\ m$ and the width is $40\ m$. So its area is $70 \times 40$.
$70 \times 40 = 2800\ m^2$

Step4: Area of green triangle

Using the area formula for a triangle $\frac{1}{2} \times base \times height$. The base of the green triangle is $60\ m$ and the height is $40\ m$. So its area is $\frac{1}{2} \times 60 \times 40$.
$\frac{1}{2} \times 60 \times 40 = 30 \times 40 = 1200\ m^2$

Step5: Total area

Sum up the areas of the three shapes: $600 + 2800 + 1200$.
$600 + 2800 + 1200 = 4600\ m^2$

Answer:

The total area of the figure is $4600\ m^2$