Question

a 70 kg cyclist bikes at a speed of 7 m/s. how much kinetic energy does the cyclist have? remember : $e_k = \frac{1}{2}mv^2$ $e_k = \boxed{?}$ j

Explanation:

Step1: Identify given values

Mass \( m = 70 \, \text{kg} \), velocity \( v = 7 \, \text{m/s} \), and the formula for kinetic energy \( E_K=\frac{1}{2}mv^2 \).

Step2: Substitute values into the formula

Substitute \( m = 70 \) and \( v = 7 \) into \( E_K=\frac{1}{2}mv^2 \):
\[

$$\begin{align*} E_K&=\frac{1}{2}\times70\times(7)^2\\ &= 35\times49 \end{align*}$$

\]

Step3: Calculate the result

Calculate \( 35\times49 = 1715 \).

Answer:

\( 1715 \)